4(x^2+17x-70)=0

Solution for 4(x^2+17x-70)=0 equation:

4(x^2+17x-70)=0

We multiply parentheses

4x^2+68x-280=0

a = 4; b = 68; c = -280;
Δ = b2-4ac
Δ = 682-4·4·(-280)
Δ = 9104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9104}=\sqrt{16*569}=\sqrt{16}*\sqrt{569}=4\sqrt{569}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-4\sqrt{569}}{2*4}=\frac{-68-4\sqrt{569}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+4\sqrt{569}}{2*4}=\frac{-68+4\sqrt{569}}{8}
$